УМОЛЯЮ!!!ПОМОГИТЕ!!!!

Question

УМОЛЯЮ!!!ПОМОГИТЕ!!!!

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Answer 1

Log[1/2](log[1/9](5x+16/3))=1
(log[1/9](5x+16/3))=(1/2)^1=1/2
(5x+16/3)=(1/9)^(1/2)=1/3
5x=1/3-16/3=(1-16)/3=-15/3=-5
x=-1