Решите 10 задание плизззз

Решите задачу:

$1)\; y=\frac{x^2-16}{|x+1|-5}\\\\OOF:\; |x+1|-5\ne 0,\; |x+1|\ne 5,\; x+1\ne \pm 5\\\\x\ne 4,x\ne -6\\\\x\in (-\infty,-6)U(4,+\infty)\\\\2)\; \frac{x^2-16}{|x+1|-5}=0\; \to \; \left \{ {{x^2-16=0} \atop {|x+1|-5\ne 0}} \right. \; \left \{ {{x=\pm 4} \atop {x\ne 4,x\ne -6}} \right. \\\\Otvet:x=-4.$

$3)........=\frac{3(a-2b)}{(a-3)(b-4)}-\frac{a^2-6b}{(a-3)(b-4)}=\frac{3a-6b-a^2+6b}{(a-3)(b-4)}=\\\\=\frac{-a(a-3)}{(a-3)(b-4)}=-\frac{a}{b-4}$