25а-4(3а-1)+7(5-2а),где а=-0,1

Question

25а-4(3а-1)+7(5-2а),где а=-0,1

Answer 1

25a-12a+4+35-14a=-a+39=39.1

Answer 2

25а-12а-4+35-14а=

=25а-12а-4+35-14а=

=25а-12а-14а-4+35=

=-1а+31=

=-1а*(-0,1)+31=

=0,1а+31.