Log(2) 182 - 2Log(2) v(5 - x) = Log(2) (11 - x) + 1
ОДЗ 5 - х >= 0
x<=5<br>11 - x >0
x<11, x<=5<br>Log(2) 182 - Log(2) (5 - x) = Log(2) (11 - x) + Log(2) 2
Log(2) 182/(5 - x) = Log(2) 2(11 - x)
182/(5 - x) = 2(11 - x)
(5 - x)(11 - x) = 91
x^2 - 16x + 55 - 91 = 0
x^2 - 16x - 36 = 0
D = (-16)^2 +4 *36 = 400
x1 = (16 + 20)/2 = 36/2 = 18 - лишний корень х <=5<br>x2 = (16 - 20)/2 = -2
Ответ -2