0\\\\D=11^2-4\cdot2\cdot5=81\\\\x_1= \dfrac{-11+9}{4} = -\dfrac{1}{2} ;\quad x_2=-5\\\\2(x+ \frac{1}{2} )(x+5)>0\\x\in(-\infty,-5)\cup(-\dfrac{1}{2},+\infty)" alt=" 5x^{2} -11x-5<7 x^{2} \\\\-2x^2-11x-5<0\\\\2x^2+11x+5>0\\\\D=11^2-4\cdot2\cdot5=81\\\\x_1= \dfrac{-11+9}{4} = -\dfrac{1}{2} ;\quad x_2=-5\\\\2(x+ \frac{1}{2} )(x+5)>0\\x\in(-\infty,-5)\cup(-\dfrac{1}{2},+\infty)" align="absmiddle" class="latex-formula">