(5\6 - 3\8) : 3\4 - (3\8 + 7\20) : 1целую9\20Заранее сяпки)

Решите задачу:

$( \frac{5}{6} - \frac{3}{8} ) : \frac{3}{4} - ( \frac{3}{8} + \frac{7}{20} ) : 1 \frac{9}{20} =( \frac{20}{24} - \frac{9}{24} ) : \frac{3}{4} - ( \frac{15}{40} + \frac{14}{40} ) : 1 \frac{9}{20} =$ $= \frac{11}{24} : \frac{3}{4} - \frac{29}{40} : 1 \frac{9}{20} = \frac{11}{24} * \frac{4}{3} - \frac{29}{40} * \frac{20}{29} = \frac{11}{6} * \frac{1}{3} - \frac{1}{2} = \frac{11}{18} - \frac{1}{2} =$ $=\frac{11}{18} - \frac{9}{18} = \frac{2}{18} = \frac{1}{9}$