Уравнение А)3^6-х=27^3х+8 Б)log2(4x-8)=log2(3x-5)

Question

Уравнение
А)3^6-х=27^3х+8
Б)log2(4x-8)=log2(3x-5)

Answer 1

А)
3^(6 - x) = 27^(3x + 8)
3^( 6 - x) = 3^(3(3x + 8)) 
6 - x = 9x + 24
9x + x = 6 - 24
10x = - 18
x = - 1,8 

Б)
log2(4x-8) = log2(3x-5)
4x - 8 = 3x - 5
4x -  3x = - 5 + 8 
x = 3