Решить уравнение 3x^2-14x/x-4=8/4-x

$3 x^{2} - \frac{14x}{x-4} = \frac{8}{4-x} \\ 3 x^{2} - \frac{14x}{x-4} -\frac{8}{4-x}=0 \\ 3 x^{2} - \frac{14x}{x-4} +\frac{8}{x-4}=0 \\ \frac{3 x^{2} (x-4)-14x(x-4)+8(x-4)}{x-4} =0 \\ \frac{ 3x^{3}-12 x^{2} -14 x^{2}+56+8x-32}{x-4} =0 \\ \frac{3 x^{3}-26 x^{2} +8x+ 24}{x-4}=0 \\$
3x³-26x²+8x+24=0
(3x³-26x²)(8x+24)=0
x²(3x-26)(8x+24)=0
x²=0 3x-26=0 8x+24=0
x=0 3x=26 8x=-24
x=26/3 x=-3