Помогите решить номер 4

$\left \{ {{3^{2x-6}<\frac{1}{27}} \atop {log_3(1-x)^2 \leq 2}} \right. \; \left \{ {{3^{2x-6}<3^{-3}} \atop {(1-x)^2 \leq 3^2}} \right. \; \left \{ {{2x-6<-3} \atop {(1-x-3)(1-x+3) \leq 0}} \right. \\\\ \left \{ {{x<\frac{3}{2}} \atop {(-2-x)(4-x) \leq 0}} \right. \; \left \{ {{x<1,5} \atop {(x+2)(x-4) \leq 0}} \right. \; \left \{ {{x<1,5} \atop {-2 \leq x \leq 4}} \right. \; \to \\\\x\in [-2;\; 1,5)$

Целые решения: х=-2,-1,0,1.