Найдите первообразную F(x) для функции y=f(x): f(x)=3cos6x-4x^(-3)+2^x

$F(x)= \frac{3}{6}sin6x-4 \frac{ x^{-3+1} }{(-3+1)}+ \frac{2 ^{x} }{ln2} +C, \\F(x)= \frac{1}{2}sin6x+ \frac{ 2 }{ x^{2} }+ \frac{2 ^{x} }{ln2} +C$

Проверка
$F`(x)=(\frac{1}{2}sin6x+ \frac{ 2 }{ x^{2} }+ \frac{2 ^{x} }{ln2} +C)`= \\ =(\frac{1}{2}sin6x)`+ (\frac{ 2 }{ x^{2} })`+ (\frac{2 ^{x} }{ln2})` +(C)`= \\ =\frac{1}{2}(sin6x)`+ 2( x^{-2})`+ \frac{1}{ln2}(2 ^{x} )` +(C)`= \\ =\frac{1}{2}cos6x(6)`+ 2\cdot(-2)( x^{-3})+ \frac{1}{ln2}(2 ^{x} )\cdotln2 +0= \\ =3cos6x- \frac{4}{ x^{3} } +2 ^{x}$