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Решите задачу:

$y`=( \sqrt{sinx})`= \frac{1}{2 \sqrt{sinx} } (sinx)`= \frac{cosx}{2 \sqrt{sinx} },$
$y`=((5 ^{3x+1}+2 x^{2}) ^{3})`=3 (5 ^{3x+1}+2 x^{2}) ^{2}\cdot (5 ^{3x+1}+2 x^{2})`= \\ =3 (5 ^{3x+1}+2 x^{2}) ^{2}\cdot( (5 ^{3x+1})`+(2 x^{2})`)= \\ =3 (5 ^{3x+1}+2 x^{2}) (5^{3x+1}\cdot ln5\cdot (3x+1)`+4x)= \\ =3 (5 ^{3x+1}+2 x^{2}) (3ln5\cdot5^{3x+1}+4x)$