Решите номер 2 пожалуйста

А)
$( \frac{4}{7}- \frac{1}{3} + \frac{5}{6} )*42=\frac{4}{7}* \frac{42}{1} - \frac{1}{3}* \frac{42}{1} + \frac{5}{6}* \frac{42}{1}= 24-14+35=45$

б)
$2 \frac{11}{15}*1 \frac{1}{19}-1 \frac{1}{19}*0,2=1 \frac{1}{19}(2 \frac{11}{15}-0,2) = \frac{20}{19}( \frac{41}{15}- \frac{1}{5} ) =\frac{20}{19}( \frac{41}{15}- \frac{3}{15})= \\ \\ =\frac{20}{19}* \frac{38}{15} = \frac{8}{3}= 2 \frac{2}{3}$