Смотри решение во вложении
Lim (sin(x)-cos(x))/cos(2x) x->π/4 (sin(x)-cos(x))/cos(2x) = (sin(x)-cos(x))/(cos²(x) - sin²(x))= =(sin(x)-cos(x))/(sin(x)-cos(x))(sin(x)+cos(x)) = =-1/(sin(x)+cos(x)) lim(1/(sin(x)+cos(x))) = -1:(√2/2+√2/2) = -1/√2 x->π/4