(\frac{1}{5})^{2*(16-x)} \\ \frac{1}{5}<1 \\ x^2+2x<32-2x \\ x^2+4x-32>0 \\ D=144 \\ x_1=-8 \\ x_2=4 " alt=" (\frac{1}{5} )^{x^2+2x}> (\frac{1}{5})^{2*(16-x)} \\ \frac{1}{5}<1 \\ x^2+2x<32-2x \\ x^2+4x-32>0 \\ D=144 \\ x_1=-8 \\ x_2=4 " align="absmiddle" class="latex-formula">
______ _______ _______
+ -8 - 4 +
(-8, 4)