А) n!+(n+1)!=n!(n+2)
n!(1+n+1)=n!(n+2)
n!(n+2)=n!(n+2)
1=1
б) (n+1)!-n!=n!n
n!(n+1-1)=n!n
n!n=n!n
1=1
в) (n-1)!+n!+(n+1)!=(n+1)²(n-1)!
(n-1)! (1+n+n(n+1))=(n+1)²(n-1)!
(n-1)!(1+n+n²+n)=(n+1)²(n-1)!
(n-1)! (1+2n+n²)=(n+1)²(n-1)!
(n+1)²(n-1)!=(n+1)²(n-1)!
1=1