Срочно!! надо на завтра!!!

Решите задачу:

$1) \frac{27}{32} * \frac{8}{162} * \frac{72}{69} = \frac{27*8*79}{32*162*69} = \frac{9*1*72}{4*162*23} = \frac{1*1*29}{4*18*23} = \\ = \frac{1*1*1}{23} = \frac{1}{23} \\ \\$

$3)( \frac{5}{8} + \frac{7}{12} )*(3 \frac{23}{58} -2 \frac{9}{58} )= 1,5\\ 1) \frac{5}{8} + \frac{7}{12} = \frac{5*3}{8*3} + \frac{7*2}{12*2} = \frac{15}{24} + \frac{14}{24} = \frac{29}{24} \\ 2)3 \frac{23}{58} -2 \frac{9}{58} =1 \frac{14}{58} =1 \frac{7}{29} \\ 3) \frac{29}{24} * \frac{36}{29} = \frac{29*36}{24*29} = \frac{3}{2} =1,5$

$5)34,17:1.7+(2 \frac{3}{5} +0.15): \frac{4}{5} -23 \frac{3}{8} = \\ =34.17:1.7+(2.75+0.15):0.8-23.375= \\ =0,35 \\ 1)2.75+0.15=2.9 \\ 2)2.9:0.8=3.625 \\ 3)34.17:1.7=20.1 \\ 4)20.1+3.625=23,725 \\ 5)23,725-23,375=0,35$

$7) \frac{12 \frac{4}{5} *3 \frac{3}{4} -4 \frac{4}{11}*4 \frac{1}{8} }{11 \frac{2}{3} *2 \frac{4}{7} } =1 \\ \\ 1)12 \frac{4}{5} *3 \frac{3}{4} = \frac{64*15}{5*4} = \frac{16*3}{1*1} =48 \\ 2)4 \frac{4}{11} *4 \frac{1}{8} = \frac{48}{11} * \frac{33}{8} = \frac{48*33}{11*8} = \frac{6*3}{1*1} =18 \\ 3)48-18=30 \\ 4)11 \frac{2}{3} *2 \frac{4}{7} = \frac{35}{3} * \frac{18}{7} = \frac{35*18}{3*7} = \frac{5*6}{1*1} =30 \\ 5)30:30=1$

Срочно!! надо ** завтра!!!