Помогите решить. Задание во вложении.

Решите задачу:

$\frac{(3\frac{7}{11}-5\cdot2 \frac{7}{22})\cdot0.08+1:1\frac{4}{7}}{2\frac{1}{3}:\frac{4}{9}-15.4\cdot0.18}= \frac{(\frac{40}{11}-5\cdot \frac{51}{22})\cdot\frac{8}{100}+1: \frac{11}{7}}{ \frac{7}{3}\cdot \frac{9}{4}-2.772} = \frac{(\frac{80}{22}-\frac{255}{22})\cdot \frac{8}{100} + \frac{7}{11}}{ \frac{21}{4}-2.772 } = \\\ =\frac{-\frac{175}{22}\cdot \frac{8}{100} + \frac{7}{11}}{ 5.25-2.772 } = \frac{-\frac{175}{275} + \frac{175}{275}}{2.478 } =\frac{0}{2.478 } =0$