Цыклическая система1. Решите систему2. найдите наименьшее n>=2014 для которого имеет...

$x_{1}-1=x_{1}x_{2}\\ x_{2}-1=x_{2}x_{3}\\ x_{3}-1=x_{3}x_{1}\\\\ x_{1}(1-x_{2})=1\\ x_{2}(1-x_{3})=1\\ x_{3}(1-x_{1})=1\\\\ x_{1}=\frac{1}{1-x_{2}}\\ x_{2}(1-\frac{1}{\frac{1}{1-x_{2}}})=1\\ x_{2}=-1\\ x_{1}=\frac{1}{2}\\ x_{3}=2\\\$

$x_{1}-1=x_{1}x_{2}\\ x_{2}-1=x_{2}x_{3}\\ x_{3}-1=x_{3}x_{4}\\ ....\\ x_{n}-1=x_{n}x_{1}\\\\ x_{1}-x_{2} =x_{2}(x_{1}-x_{3})\\ x_{3}-x_{2}=x_{3}(x_{4}-x_{2})...$
Откуда следует что $n=2016$