Помогите решить за 7 класс

$\left \{ {{10x+y=6(x+y)+2} \atop {10x+y=5xy+2}} \right. \; \left \{ {{10x+y=6x+6y+2} \atop {10x+y=5xy+2}} \right. \; \left \{ {{4x-5y=2} \atop {10x+y=5xy+2}} \right. \\\\ \left \{ {{x=\frac{2+5y}{4}} \atop {10\cdot \frac{2+5y}{4}+y=5y\cdot \frac{2+5y}{4}+2\; |\cdot 4}} \right. \\\\10(2+5y)+4y=5y(2+5y)+8\\\\20+50y+4y=10y+25y^2+8\\\\25y^2-44y-12=0\\\\D/4=784,\; y_1=\frac{22-28}{25}=-0,24;\; \; y_2=\frac{22+28}{25}=2\\\\x_1=\frac{2-5\cdot 0,24}{4}=0,2;\; \; x_2=\frac{2+5\cdot 2}{4}=3$

Ответ: (0,2 ; -0,24), (3;2).