CH3COOH+C2H5OH=CH3COOC2H5=H2O
V(C2H5OH)=\frac{m}{M}
M(C3H5OH)=12\cdot2+5+16+1=46
V(C2H5OH)=\frac{1.2}{46}=0.02 г/моль
М(CH3COOH)=12+3+12+16+16+1=60
V(CH3COOH)=\frac{1.8}{60}=0.03 г/моль
на 1 моль - 1 моль
на 0.02 моль - х моль
Х=\frac{0.02\cdot1}{1}=0.02
m(CH3COOC2H5)=V\cdotM=0.02\cdot88=1.76