Помогите решить уравнение (y-35)+12=32; 56-(x+12)=24; (25-y)+18=58

Question

Помогите решить уравнение (y-35)+12=32; 56-(x+12)=24; (25-y)+18=58

Answer 1

(у - 35) + 12 = 32                        56 - (х + 12) = 24

(у - 35) = 32 - 12                         х + 12 = 56 - 24

у - 35 = 20                                   х + 12 = 32 

у = 20 + 35                                  х = 32 - 12

у = 55                                          х = 20 

Проверка:                                   Проверка:

(55 - 35) + 12 = 32                       56 - (20 + 12) = 24

20 + 12 = 32                                 56 - 32 = 24

32 = 32                                         24 = 24

(25 - у) + 18 = 58

25 - у = 58 - 18

25 - у = 40

у = 25 - 40

у = - 15

Проверка:

(25 - (-15)) + 18 = 58

25 + 15 + 18 = 58

58 = 58  

Answer 2

1. (у-35)+12=32
y=32-12+35
y=55
2. 56-(x+12)=24
56-x-12=24
-x=24+12-56
- x=-20
x=20
3. (25-y)+18=58
-y=58-18-25
-y=15
y=-15
Может быть и так)