РЕШИТЕ СИСТЕМУ УРАВНЕНИЙx-2y=-8x/4+y-2/3=-1

Решите задачу:

$\left \{ {{x-2y=-8} \atop { \frac{x}{4}+y- \frac{2}{3}=-1}} \right. \\ \\ \left \{ {{x=2y-8} \atop {\frac{3x+12y-8}{12}=-1}} \right. \\ \\ \left \{ {{x=2y-8} \atop {3x+12y-8=-12}} \right. \\ \\ \left \{ {{x=2y-8} \atop {3x+12y=8-12}} \right. \\ \\ \left \{ {{x=2y-8} \atop {3x+12y=-4}} \right. \\ \\ 3(2y-8)+12y=-4 \\ 6y-24+12y=-4 \\ 18y=20 \\ y= \frac{20}{18} = \frac{10}{9} =1 \frac{1}{9} \\ \\ x=2(\frac{10}{9})-8=\frac{20-72}{9}=- \frac{52}{9} =-5 \frac{7}{9}$