3/(x-1)-5/(x+1)-8=13/(1-x^2)
(3(х+1)-5(х-1)-8(х+1)(х-1)-13)/(х-1)(х+1)=0
3х+3-5х+5-8+8Х^2=0
8х^2-2х=0
2х(4х-1)=0
система
2х=0 х=0
4х-1=0 4х=1 х= 1/4
Ответ: х=1/4, х=0