√х+12-√5-х=3 допоможіть
(√(x+12))∧2 = (√(5 - x) + 3))∧2 x+12 = 5 - x + 6*(√(5-x)) + 9 2x - 2 = 6*(√(5 - x) (x - 1)∧2 = (3*√(5-x))∧2 x∧2 - 2x + 1 = 9*(5 -x) x∧2 + 7x - 44 = 0 x1 = -11 x2 = 4