1\\\\\frac{x-2}{5-x}-1>0\\\\\frac{x-2-5+x}{5-x}>0\\\\\frac{2x-7}{-(x-5)}>0\\\\\frac{2x-7}{x-5}<0\\\\2x-7=0,\; x=\frac{7}{2}=3,5\\\\x-5=0,\; x=5\\\\+++(3,5)---(5)+++\\\\x\in (3,5\; ;5)" alt="\frac{x-2}{5-x}>1\\\\\frac{x-2}{5-x}-1>0\\\\\frac{x-2-5+x}{5-x}>0\\\\\frac{2x-7}{-(x-5)}>0\\\\\frac{2x-7}{x-5}<0\\\\2x-7=0,\; x=\frac{7}{2}=3,5\\\\x-5=0,\; x=5\\\\+++(3,5)---(5)+++\\\\x\in (3,5\; ;5)" align="absmiddle" class="latex-formula">