1) tg A = \frac{BC}{AC}
\frac{2 \sqrt{10} }{3} = \frac{BC}{12}
BC= \frac{2 \sqrt{10}*12 }{3} = \frac{ \sqrt{40} *12}{3} = \frac{ \sqrt{40*144} }{3} = \sqrt{ \frac{5760}{9} }
2) т. Пифагора
AB^{2} = AC^{2} + BC^{2}
AB^{2} = 12^{2} + \sqrt{640} ^{2} = 144+640=784
\\*AB = 28
Ответ: 28