(\frac{1}{25})^{\frac{3}{10}}\\\\(\frac{1}{5}^{\frac{x(x+2)}{5}}>(\frac{1}{5})^{\frac{3}{5}}\\\\\frac{x(x+2)}{5}<\frac{3}{5}\\\\x^2+2x-3<0\\\\x_1=1,\; x_2=-3\; (teor.\; Vieta)" alt="(\frac{1}{5})^{\frac{x(x+2)}{5}}>(\frac{1}{25})^{\frac{3}{10}}\\\\(\frac{1}{5}^{\frac{x(x+2)}{5}}>(\frac{1}{5})^{\frac{3}{5}}\\\\\frac{x(x+2)}{5}<\frac{3}{5}\\\\x^2+2x-3<0\\\\x_1=1,\; x_2=-3\; (teor.\; Vieta)" align="absmiddle" class="latex-formula">