Помогите пожалуйста...................................

Решите задачу:

$\frac{11y}{20} =16:80 \\\ \frac{11y}{20} =0.2 \\\ y=0.2\cdot20:11 \\\ y= \frac{4}{11}$

$7.2:2.7= \frac{32y}{3} \\\ \frac{32y}{3} = \frac{72}{27} \\\ y= \frac{72\cdot3}{32\cdot27} \\\ y=0.25$

$5.1:8.7= \frac{34y}{29} \\\ \frac{34y}{29} = \frac{51}{87} \\\ y= \frac{51\cdot29}{34\cdot87} \\\ y=0.5$

$\frac{6y}{49} =50:245 \\\ \frac{6y}{49} = \frac{20}{245} \\\ y= \frac{20\cdot49}{6\cdot245} \\\ y= \frac{4}{6} =\frac{2}{3}$