помогите решить 2 уравнения

$\sqrt{x-2} =4 \\\ x-2 =4^2 \\\ x-2=16 \\\ x=18$
Ответ: 18

$\sqrt{x+1} =1-x \\\ \left \{ {{ x+1 =(1-x)^2} \atop {1-x \geq 0}} \right. \\\ \left \{ {{ x+1 =1-2x+x^2} \atop {x \leq 1}} \right. \\\ \left \{ {{ x^2-3x=0} \atop {x \leq 1}} \right. \\\ \left \{ {{ x(x-3)=0} \atop {x \leq 1}} \right. \\\ \left \{ {{ x_1=0; \ x_2=3} \atop {x \leq 1}} \right. \\\ x=0$
Ответ: 0