Помогите решить 1/3+0,3; 3/5-0,76;-1/6-0,5;3/20-0,95

Решите задачу:

$\frac{1}{3} + 0,3 = \frac{1}{3} + \frac{3}{10} = \frac{1*10+3*3}{30} = \frac{19}{30}$
$\frac{3}{5} - 0,76 = \frac{3}{5} - \frac{76}{100} = \frac{15}{25} - \frac{19}{25} = \frac{15-19}{25} = - \frac{4}{25}$
$- \frac{1}{6} - 0,5 = - ( \frac{1}{6} + \frac{1}{2} ) = - ( \frac{1}{6} + \frac{3}{6} ) = - ( \frac{1+3}{6} ) = - \frac{4}{6} =- \frac{2}{3}$
$\frac{3}{20} - 0,95 = \frac{3}{20} - \frac{95}{100} = \frac{3}{20} - \frac{19}{20}= \frac{3-19}{20} = -\frac{16}{20} = - \frac{4}{5}$