Помогите решить уравнение! 1) 3х/3=1-x/2 2)1/3(5/12-4m)=4/9(1 1/2m-3/8) 3)x(-5)(x+2,5)=0

1)
$\frac{3x}{3}=1-\frac{x}{2} \\ \\ x=1-\frac{x}{2} \\ \\ x+\frac{x}{2}=1 \\ \\ \frac{2x+x}{2}=1 \\ \\ 3x=2 \\ \\ x= \frac{2}{3}$

2)
$\frac{1}{3}(\frac{5}{12}-4m)=\frac{4}{9}(1\frac{1}{2}m-\frac{3}{8}) \\ \\ \frac{1}{3}(\frac{5-48m}{12})=\frac{4}{9}(\frac{12m-3}{8}) \\ \\ \frac{5-48m}{12*3}=\frac{12m-3}{2*9} \\ \\ \frac{5-48m}{36}=\frac{12m-3}{18} \\ \\ 18(5-48m)=36(12m-3) \\ 5-48m=2(12m-3) \\ 5-48m=24m-6 \\ -48m-24m=-6-5 \\ -72m=-11 \\ m= \frac{11}{72}$

3)
$x(-5)(x+2,5)=0 \\ \\ x(-5)(x+\frac{25}{10})=0 \\ \\ x(-5)(x+\frac{5}{2})=0 \\ \\ x(-5x-\frac{25}{2})=0 \\ x=0 \\ \\ -5x-\frac{25}{2}=0 \\ \\ -5x=\frac{25}{2} \\ \\ x=\frac{25}{2}:(-5) \\ \\ x=\frac{25}{2}*(-\frac{1}{5}) =-\frac{5}{2}$