Пож срочно пол ответ
Tg1140⁰=tg(6π+60⁰)=tg60⁰=√3; sin(-15π/4)=-sin(15π/4)=-sin(4π-π/4)=sinπ/4=√2/2; sinα·cosα·tgα·ctgα α=134⁰=(90⁰+44⁰)=(π/2+44⁰) sin(π/2+44)·cos(π/2+44)·tg(π/2+44)·(ctg(π/2+44)= =cos44⁰·(-sin44⁰)·(-tg44⁰)(-ctg44⁰)=-cos44⁰·sin44⁰·ctg44⁰·tg44⁰