1) x+(4x²+5x)/(x+2)(x-3)≤9/5(x-3) +(5x+1)/5(x+2)
(5x(x²-x-6)+5(4x²+5x)-9(x+2)-(5x+1)(x-3))/5(x-3)(x+2)≤0
(5x³-5x²-30x+20x²+25x-9x-18-5x²+15x-x+3)/5(x-3)(x+2)≤0
(5x³+10x²-15)/5(x-3)(x+2)≤0
5(x³+2x²-3)/5(x-3)(x+2)≤0
(x³+2x²-3)/(x-3)(x+2)≤0
(x-1)(x²+3x+3)/(x-3)(x+2)≤0
x²+3x+3>0 при любом х,т.к. D<0<br>x=1 x=3 x=-2
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-2 1 3
x∈(-≈;-2) U [1;3)
2)(5^x)/5 +125/(5^x)<26<br>5^2x-130*5^x+625<0<br>5^x=a
a²-130a+625<0<br>a1+a2=130 U a1*a2=625⇒a1=5 U a2=125
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5 125
5Объединим решения
x∈(-≈;-2) U [1;3) и ∈(1;3)⇒х∈(1;3)