1/3+1,2(2,3-0,061:0,2)=

Решите задачу:

$= \frac{1}{3} +1,2*(2,3- \frac{61}{1000}: \frac{2}{10} )=\frac{1}{3} +1,2*(2,3- \frac{61}{1000}: \frac{1}{5} )= \\ =\frac{1}{3} +1,2*(2,3- \frac{61}{1000}* \frac{5}{1} )=\frac{1}{3} +1,2*(2,3- \frac{61}{200})= \\ =\frac{1}{3} +1,2*( \frac{23}{10} - \frac{61}{200})=\frac{1}{3} +1,2*( \frac{23*20}{10*20} - \frac{61}{200})= \\ =\frac{1}{3} +1,2*( \frac{460}{200} - \frac{61}{200})=\frac{1}{3} + \frac{12}{10} * \frac{399}{200} = \\ = \frac{1}{3} + \frac{1197}{500}= \frac{500+1197*3}{1500}= \\$
$= \frac{4091}{1500}=2 \frac{1091}{1500}$