Найдите производные функций:а) b) c) d)

Решите задачу:

$( \frac{1+2x}{3-5x})'= \frac{(1+2x)'(3-5x)-(1+2x)(3-5x)'}{(3-5x)^2}= \frac{6-10x+5+10x}{(3-5x)^2}= \frac{11}{(3-5x)^2}=$ $\frac{11}{25x^2-30x+9}$

$(\frac{x^2}{2x-1})'= \frac{4x^2-2x-2x^2}{(2x-1)^2}= \frac{2x^2-2x}{(2x-1)^2}= \frac{2x(x-1)}{(2x-1)^2}$

$( \frac{3x-2}{5x+8})'= \frac{15x+24-15x+10}{(5x+8)^2}= \frac{34}{(5x+8)^2}= \frac{34}{25x^2+80x+64}$

$( \frac{3-4x}{x^2})'= \frac{-4x^2-6x+8x^2}{x^4}= \frac{4x^2-6x}{x^4}= \frac{2x(2x-3)}{x^4}= \frac{4x-6}{x^3}$