Помогите решить ...0,25*(1/4)^(10-x)>32

Question

Помогите решить ...
0,25*(1/4)^(10-x)>32

Answer 1

0,25*(1/4)^(10-x)>32
(1/4)^(11-x)>(1/2)^(-5)
(1/2)^2(11-x)>(1/2)^(-5), меняем знак т.к. 1/2<1<br>2(11-x)<-5<br>22-2x<-5<br>2x>27
x=13.5
С: