(-6x-1)(4-5x)(x+3)>0

Question

(-6x-1)(4-5x)(x+3)>0

Answer 1

0, \\ -6\cdot(-5)\cdot(x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ 30(x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ (x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ (x+\frac{1}{6})(x-\frac{4}{5} )(x+3)=0, \\ x_1=-3, x_2=- \frac{1}{6}, x= \frac{4}{5}, \\ x\in(-3;- \frac{1}{6})\cup(\frac{4}{5};+\infty)" alt="(-6x-1)(4-5x)(x+3)>0, \\ -6\cdot(-5)\cdot(x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ 30(x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ (x+\frac{1}{6})(x-\frac{4}{5} )(x+3)>0, \\ (x+\frac{1}{6})(x-\frac{4}{5} )(x+3)=0, \\ x_1=-3, x_2=- \frac{1}{6}, x= \frac{4}{5}, \\ x\in(-3;- \frac{1}{6})\cup(\frac{4}{5};+\infty)" align="absmiddle" class="latex-formula">

Comments

Спасибо,а в каких скобках?

---

в каких написано

---

Спасибо,выручил

---

пупизойд