Задание во вложении 5 6 7 номера

№5:
$3 \frac{4}{33} -x=1 \frac{19}{22} , x=3 \frac{4}{33} -1 \frac{19}{22} , x= \frac{103}{11*3} - \frac{41}{11*2} , x= \frac{103*2-41*3}{11*2*3} ,$ $x= \frac{206-203}{66} , x= \frac{3}{66} = \frac{1}{22}$

№6:
$20-8 \frac{5}{12} -(8 \frac{5}{12} - 1\frac{3}{8} )=\frac{240-101}{12} - \frac{101*2-11*3}{24} = \frac{278-169}{24} = \frac{109}{24}$

№7:
$(23 \frac{3}{4} -x)+8 \frac{5}{6} =11 \frac{4}{21} , \frac{95}{4} -x= \frac{235}{21}- \frac{53}{6} , \frac{95}{4} -x= \frac{235*6-53*21}{126} ,$ $\frac{95}{4} -x= \frac{1410-1113}{126} , -x= \frac{297}{126} - \frac{95}{4} , x= \frac{95}{4} - \frac{33}{14} , x= \frac{95*7-33*2}{28} ,$ $x= \frac{665-66}{28} = \frac{599}{28} =21 \frac{11}{28}$