Дам 30, срочно, срочно, срочно

Решите задачу:

$25/28 \sqrt{ \frac{101^2-20^2}{125}} -1/45* \sqrt{115^2-110^2}= \\ 25/28 \sqrt{ \frac{(101-20)(101+20)}{125}} -1/45* \sqrt{(115-110)(115+110)}= \\ 25/28 \sqrt{ \frac{81*121}{125}} -1/45* \sqrt{5*225}= \\ 25/28 *9*11\sqrt{ \frac{1}{5*25}} -1/45* 15 \sqrt{5}= \\ 25/28 *99/5\sqrt{ \frac{1}{5}} -1/3 \sqrt{5}= \\ 5/28 *99\sqrt{ \frac{1}{5}} -1/3 \sqrt{5}=99/28\sqrt{ \frac{25}{5}} -1/3 \sqrt{5}= \\ 297/84\sqrt{5} -28/84 \sqrt{5}=269/84\sqrt{5}=3 \frac{17}{84} \sqrt{5}$

$-3/10 \sqrt{\frac{115^2-15^2}{130}} -1/17 \sqrt{ \frac{273^2-16^2}{257} } = \\ -3/10 \sqrt{\frac{(115-15)(115+15)}{130}} -1/17 \sqrt{ \frac{(273-16)(273+16)}{257} } = \\ -3/10 \sqrt{\frac{100*130}{130}} -1/17 \sqrt{ \frac{257*289}{257} } = \\ -3/10 \sqrt{100} -1/17 \sqrt{289 } =-3/10 *10 -1/17 *17} = -3-1=-4$