Nomer 1.2.3 pomogite pojaluysta srocno)

$1)A\bigcup B={3, 4,8,5,2,7,9}, \\A\bigcap B={4,8.2}$
$2) [-2;9)\bigcup [1;12]=[-2;12],$
$[-2;9)\bigcap [1;12] =[1;9]$ 0\rbrace=\lbrace x|2x>4\rbrace=\rbrace=\lbrace x|x>2\rbrace(2;+\infty)," alt="(-7;-3)\bigcup (-4;8] =(-7;8] \\ )(-7;-3)\bigcap (-4;8] =(-4;-3)] , \\ 3) D(f)=\lbrace x|3x+9 \neq 0\rbrace=\lbrace x|x \neq -3\rbrace=(-\infty;-3)\bigcup (-3;+\infty), \\ D(g)=\lbrace x|2x-4 > 0\rbrace=\lbrace x|2x>4\rbrace=\rbrace=\lbrace x|x>2\rbrace(2;+\infty)," align="absmiddle" class="latex-formula">