√0x=20m/cax= - 4m/c2t1=5ct2=7c√x-? √x2-?

Question

√0x=20m/c
ax= - 4m/c2
t1=5c
t2=7c
√x-? √x2-?

Answer 1

√0x=20m/c
ax= - 4m/c2
t1=5c
t2=7c
√x-? √x2-?
Решение
Vx(t)=Vox +ax*t
Vx(t)=20-4*t
Vx(5)=20-20=0
Vx(7)=20-28=-8 м/с