Br2 NaOh H2OiHg H2 HclС2H4===>A=====>B========>C======>D=====>E

Question

Br2 NaOh H2OiHg H2 Hcl
С2H4===>A=====>B========>C======>D=====>E

Answer 1

C2H4+Br2=C2H4Br2
C2H4Br2+2NaOH(спирт, р-р)=2NaCl+2H2O+C2H2
C2H2+H2O=CH3COH в присутствии солей ртути (II)
CH3COH + H2=C2H5OH
C2H5OH + HCl=C2H5Cl+H2O