Упростите выражение: √((9√18-√3)/(√18-√3)+√6) -√((6√3-10)^2 )

Решите задачу:

$\sqrt{\left[(9\sqrt{18}-\sqrt3):(\sqrt{18}-\sqrt3)\right]+\sqrt6}-\sqrt{\left(6\sqrt3-10\right)^2}\\\\=\sqrt{\left[(9\sqrt{9\cdot2}-\sqrt3):(\sqrt{9\cdot2}-\sqrt3)}\right]+\sqrt6}-|6\sqrt3-10|\\\\=\sqrt{\left[(27\sqrt2-\sqrt3):(3\sqrt2-\sqrt3)\right]+\sqrt6}-(6\sqrt3-10)\\\\=\sqrt{\frac{27\sqrt2-\sqrt3}{3\sqrt2-\sqrt3}\cdot\frac{3\sqrt2+\sqrt3}{3\sqrt2+\sqrt3}+\sqrt6}-6\sqrt3+10$

$=\sqrt{\frac{81\cdot2+27\sqrt6-3\sqrt6-3}{(3\sqrt2)^2-(\sqrt3)^2}+\sqrt6}-6\sqrt3+10\\\\=\sqrt{\frac{159+24\sqrt6}{9\cdot2-3}+\sqrt6}-6\sqrt3+10\\\\=\sqrt{\frac{159+24\sqrt6}{18-3}+\sqrt6}-6\sqrt3+10\\\\=\sqrt{\frac{159+24\sqrt6}{15}+\sqrt6}-6\sqrt3+10\\\\=\sqrt{\frac{53+8\sqrt6}{5}+\sqrt6}-6\sqrt3+10\\\\=\sqrt{\frac{53+8\sqrt6}{5}+\frac{5\sqrt6}{5}}-6\sqrt3+10\\\\=\sqrt{\frac{53+13\sqrt6}{5}}-6\sqrt3+10$