Tg(arcsin 12/13) вычислить

Решите задачу:

$1)sin(arcsin \alpha )= \alpha \\ 2)sin^2(arcsin \alpha )= \alpha^2 \\ 3)tg \alpha = \frac{sin \alpha }{cos \alpha } \\ 4)cos \alpha = \sqrt{1-sin ^{2} \alpha } \\ \\ cos(arcsin \frac{12}{13} )= \sqrt{1-sin^2(arcsin \frac{12}{13} )}= \sqrt{1-( \frac{12}{13})^2 } \\ = \sqrt{1- \frac{144}{169} } = \sqrt{ \frac{25}{169} } = \frac{5}{13} \\ \\ tg(arcsin \frac{12}{13} )= \frac{sin(arcsin \frac{12}{13} )}{cos(arcsin \frac{12}{13} )} = \frac{12}{13} : \frac{5}{13} = \frac{12}{13} : \frac{13}{5}=$
$= \frac{12}{5} =2.4\\ \\ OTBET: 2.4$