(X+5)^2+(x-2)^2+(x-7)(x+7)=11x+80

Question

(X+5)^2+(x-2)^2+(x-7)(x+7)=11x+80

Answer 1

(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+80
x^2 + 10x + 25 + x^2 - 4x + 4 + x^2 - 49 - 11x - 80 = 0 
3x^2 - 5x - 100 =
D = 25 + 1200 = 1225 
x₁ =  - 5 ;
x₂ = 6²/³