Помогите решить пожалуйста!!!!!!!!!!!!!!

Question 1

Question 2

Решите задачу:

$\left \{ {{ \sqrt{\frac{y}{x}} - 2 \sqrt{\frac{x}{y}} = 1 ,} \atop { \sqrt{5x+y} + \sqrt{5x-y} = 4;}} \right. \ \ \ \left \{ {{ (\sqrt{\frac{y}{x}} - 2 \sqrt{\frac{x}{y}})^2 = 1 , } \atop { (\sqrt{5x+y} + \sqrt{5x-y})^2 = 4^2 ; }} \right. \\$
$\left \{ {{ \frac{y}{x} - 4 \sqrt{\frac{y}{x}}\sqrt{\frac{x}{y}} +4\frac{x}{y} = 1 , } \atop { 5x+y+ 2\sqrt{5x+y}\sqrt{5x-y} +5x-y}= 16 ; }} \right. \ \ \ \left \{ {{ \frac{y}{x} - 4 +\frac{4x}{y} = 1 , } \atop { 2\sqrt{(5x)^2-y^2}}= 16-10x ; }} \right. \\$
$\left \{ {{ \frac{y^2-5xy+4x^2}{xy}=0 , } \atop { (2\sqrt{25x^2-y^2}})^2= (16-10x)^2 ; }} \right. \ \ \ \left \{ {{ y^2-5xy+4x^2=0 , } \atop { 100x^2-4y^2= 256-320x+100x^2 ; }} \right. \\$
$\left \{ {{ y^2-5xy+4x^2=0 , } \atop { y^2-80x+64=0 ; }} \right. \\ y^2-2\cdot \frac{5}{2}xy+ \frac{25}{4}x^2- \frac{9}{4} x^2=0,\\ (y- \frac{5}{2} x)^2-( \frac{3}{2} x)^2=0, \\ (y- \frac{5}{2} x- \frac{3}{2} x)(y- \frac{5}{2} x + \frac{3}{2} x)=0, \\ (y-4x)(y-x)=0, \\ \left \ [ {{y=4x,} \atop {y=x;}} \right. \\ 16x^2-80x+64=0, \\ x^2-5x+4=0, \\ x_1=1, x_2=4, \\ x^2-80x+64=0, \\ D_{/4}=1600-64=1536, \\ x_3=20-8 \sqrt{6} , x_4=20+8 \sqrt{6} ;\\$
$y_1=4, y_2=16, y_3=20-8 \sqrt{6} , y_4=20+8 \sqrt{6}; \\$