131 132 133 134 135номера помогите срочно

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133.
1,} \atop {x^2-9 \leq 9;}} \right. \left \{ {{-x>-2,} \atop {x^2-18 \leq 0;}} \right. \left \{ {{x<2,} \atop {(x+ \sqrt{18})(x- \sqrt{18}) \leq 0;}} \right. \left \{ {{x<2,} \atop {-3 \sqrt2 \leq x \leq 3 \sqrt2;}} \right. \\ -3 \sqrt2 \leq x<2; \\ x\in[-3 \sqrt2;2)." alt=" \left \{ {{3-x>1,} \atop {x^2-9 \leq 9;}} \right. \left \{ {{-x>-2,} \atop {x^2-18 \leq 0;}} \right. \left \{ {{x<2,} \atop {(x+ \sqrt{18})(x- \sqrt{18}) \leq 0;}} \right. \left \{ {{x<2,} \atop {-3 \sqrt2 \leq x \leq 3 \sqrt2;}} \right. \\ -3 \sqrt2 \leq x<2; \\ x\in[-3 \sqrt2;2)." align="absmiddle" class="latex-formula">

0;}} \right. \left \{ {{x^2 -4 \geq 0,} \atop {x>3;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {x>3;}} \right. \left \{ {{ \left [ {{x \leq -2,} \atop {x \geq 2,}} \right. } \atop {x>0;}} \right. \left [ {{ \left \{ {{x \leq -2,} \atop {x>3;}} \right. } \atop { \left \{ {{x \geq 2,} \atop {x>3;}} \right. }} \right. \left [ {{x\in\varnothing, } \atop { x>3; }} \right. \\ x>3, \\ x\in(3;+\infty)." alt=" \left \{ {{x^2 \geq 4,} \atop {x-3>0;}} \right. \left \{ {{x^2 -4 \geq 0,} \atop {x>3;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {x>3;}} \right. \left \{ {{ \left [ {{x \leq -2,} \atop {x \geq 2,}} \right. } \atop {x>0;}} \right. \left [ {{ \left \{ {{x \leq -2,} \atop {x>3;}} \right. } \atop { \left \{ {{x \geq 2,} \atop {x>3;}} \right. }} \right. \left [ {{x\in\varnothing, } \atop { x>3; }} \right. \\ x>3, \\ x\in(3;+\infty)." align="absmiddle" class="latex-formula">

x,}} \right. \left \{ {{-x(x-6) \geq 0,} \atop {-3x>-3,}} \right. \left \{ {{x(x-6) \leq 0,} \atop {x<1,}} \right. \left \{ {{0 \leq x \leq 6,} \atop {x<1,}} \right. \\ 0 \leq x <1, \\ x\in(0;1)." alt=" \left \{ {{6x-x^2 \geq 0,} \atop {3-2x>x,}} \right. \left \{ {{-x(x-6) \geq 0,} \atop {-3x>-3,}} \right. \left \{ {{x(x-6) \leq 0,} \atop {x<1,}} \right. \left \{ {{0 \leq x \leq 6,} \atop {x<1,}} \right. \\ 0 \leq x <1, \\ x\in(0;1)." align="absmiddle" class="latex-formula">
134.
$\left \{ {{x^2<9,} \atop {(3x-5)^2<1;}} \right. \left \{ {{x^2-9<0,} \atop {(3x-5)^2-1<0;}} \right. \left \{ {{(x+3)(x-3)<0,} \atop {(3x-4)(3x-6)<0;}} \right. \left \{ {{-3<x<3,} \atop { \frac{4}{3}<x<2;}} \right. \\ 1\frac{1}{3}<x<2, \\ x\in(1\frac{1}{3};2).$

$\left \{ {{x^2 \geq 4,} \atop {(2-5x)^2 \geq 16;}} \right. \left \{ {{x^2-4 \geq 0,} \atop {(2-5x)^2-16 \geq 0;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {(18-5x)(-14-5x) \geq 0;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {(x- \frac{18}{5})(x+ \frac{14}{5}) \geq 0;}} \right. \\ \left \{ {{ \left [ {{x \leq -2,} \atop {x \geq 2;}} \right. } \atop { \left [ {{x \leq -2,8,} \atop {x \geq 3,6;}} \right. }} \right. \left [ {{x \leq -2,8,} \atop {x \geq 3,6;}} \right.$
$x\in(-\infty;-2,8]\cup[3,6;+\infty).$

$\left \{ {{x^2<16,} \atop {(x-2)^2 \geq 9;}} \right.\left \{ {{x^2-16<0,} \atop {(x-2)^2-9 \geq 0;}} \right. \right. \left \{ {{(x+4)(x-4)<0,} \atop {(x+7)(x-11) \geq 0;}} \right. \left \{ {{-4<x<4,} \atop { \left [ {{x \leq -7,} \atop {x \geq 11;}} \right. }} \right. \\ x\in\varnothing.$

arsenlevadniy_zn (93.5k баллов) 27 Март, 18