0\end{cases}\Rightarrow\begin{cases}x\geq-1\frac12\\x>-1\frac13\end{cases}\Rightarrow x\in\left(-1\frac13;\;+\infty\right)" alt="f(x)=\frac{\sqrt{4x+6}}{\sqrt{3x+4}}\\O.O.\Phi.:\\\begin{cases}4x+6\geq0\\3x+4>0\end{cases}\Rightarrow\begin{cases}x\geq-1\frac12\\x>-1\frac13\end{cases}\Rightarrow x\in\left(-1\frac13;\;+\infty\right)" align="absmiddle" class="latex-formula">