Ребята!!!! Вкрай нужно ** завтра!!! =(((((!!!

Question 1

Ребята!!!! Вкрай нужно на завтра!!! =(((((!!!

Question 2

$\frac{3 \frac{1}{3}:10+0,175:0,35}{1,75-1 \frac{11}{17}* \frac{51}{56} }- \frac{ \frac{1}{18}: \frac{1}{15}:1.4 }{(0.5- \frac{1}{9})*3} = \frac{ \frac{10}{3}* \frac{1}{10}+0,5}{1,75-\frac{28}{17}* \frac{51}{56} }- \frac{ \frac{1}{18}* \frac{15}{1}:1.4 }{( \frac{5}{10} - \frac{1}{9})*3} = \\ \frac{ \frac{1}{3}+0,5}{1,75-\frac{1}{17}* \frac{51}{2} }- \frac{ \frac{1}{6}* \frac{5}{1}* \frac{1}{1.4}}{( \frac{1}{2} - \frac{1}{9})*3} =$
$= \frac{ \frac{1}{3}+ \frac{5}{10}}{1,75-\frac{1}{1}* \frac{3}{2} }- \frac{ \frac{1}{6}* \frac{5}{1}* \frac{10}{14}}{( \frac{9}{18} - \frac{2}{18})*3} = \frac{ \frac{10}{30}+ \frac{15}{30}}{1,75- \frac{3}{2} }- \frac{ \frac{1}{6}* \frac{5}{1}* \frac{5}{7}}{ \frac{7}{18}*3} = \\ \frac{ \frac{25}{30}}{1,75- 1.5 }- \frac{ \frac{25}{42}}{ \frac{7}{6}} = \frac{ \frac{25}{30}}{0.25 }- \frac{25}{42}* \frac{6}{7} = \frac{25}{30}* \frac{1}{0.25}- \frac{25}{7}* \frac{1}{7} = \\$
$\frac{100}{30}- \frac{25}{49} = \frac{10}{3}- \frac{25}{49} = \frac{490}{147}- \frac{75}{147} = \frac{415}{147} = 2\frac{121}{147}$

Мне кажется, Вы во второй дроби в знаменателе написали :1,4, а надо *1,4...
Если я права, то будет
$\frac{3 \frac{1}{3}:10+0,175:0,35}{1,75-1 \frac{11}{17}* \frac{51}{56} }- \frac{ \frac{1}{18}: \frac{1}{15}*1.4 }{(0.5- \frac{1}{9})*3} = \frac{ \frac{10}{3}* \frac{1}{10}+0,5}{1,75-\frac{28}{17}* \frac{51}{56} }- \frac{ \frac{1}{18}* \frac{15}{1}*1.4 }{( \frac{5}{10} - \frac{1}{9})*3} = \\ \frac{ \frac{1}{3}+0,5}{1,75-\frac{1}{17}* \frac{51}{2} }- \frac{ \frac{1}{6}* \frac{5}{1}* 1.4}{( \frac{1}{2} - \frac{1}{9})*3} =$
$= \frac{ \frac{1}{3}+ \frac{5}{10}}{1,75-\frac{1}{1}* \frac{3}{2} }- \frac{ \frac{5}{6}*1.4}{( \frac{9}{18} - \frac{2}{18})*3} = \frac{ \frac{10}{30}+ \frac{15}{30}}{1,75- \frac{3}{2} }- \frac{ \frac{7}{6}}{ \frac{7}{18}*3} = \\ \frac{ \frac{25}{30}}{1,75- 1.5 }- \frac{ \frac{7}{6}}{ \frac{7}{6}} = \frac{ \frac{25}{30}}{0.25 }- 1 = \frac{25}{30}* \frac{1}{0.25}- 1 =100/30-1=10/3-1= \\ 3\frac{ 1}{3}-1=2 \frac{ 1}{3}$