2х+у=-1 Х^2+2у=3 решить систему

Решите задачу:

$\left \{ {{2x+y=-1} \atop { x^{2} +2y=3}} \right. \left \{ {{y=-1-2x} \atop { x^{2} +2(-1-2x)=3}} \right. \left \{ {{y=-1-2x} \atop { x^{2} -2-4x-3=0}} \right. \left \{ {{y=-1-2x} \atop { x^{2} -4x-5=0}} \right. \left \{ {{y=-1-2x} \atop {D=36}} \right. \\ \left \{ {{y=-1-2x} \atop { \left \{ {{x=5} \atop {x=-1}} \right. }} \right. \left \{ {{x=5, y=-11} \atop {x=-1, y=1}} \right.$